Question

the denominator of a rational number is greater than its numerator by 14 .if the numerator and the denominator are both increased by 11 the New rational number obtained is 2 by 3. Find the original rational number​

Answer 1

Let the numerator of the rational number be x.

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.The rational number will be \(\frac{x}{x+8}\)

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.The rational number will be \(\frac{x}{x+8}\)According to the given condition,

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.The rational number will be \(\frac{x}{x+8}\)According to the given condition,\(\frac{x+17}{x+8-1} = \frac{3}{2}\)

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.The rational number will be \(\frac{x}{x+8}\)According to the given condition,\(\frac{x+17}{x+8-1} = \frac{3}{2}\)

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.The rational number will be \(\frac{x}{x+8}\)According to the given condition,\(\frac{x+17}{x+8-1} = \frac{3}{2}\) \(\frac{x+17}{x+7} = \frac{3}{2}\)

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.The rational number will be \(\frac{x}{x+8}\)According to the given condition,\(\frac{x+17}{x+8-1} = \frac{3}{2}\) \(\frac{x+17}{x+7} = \frac{3}{2}\)

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.The rational number will be \(\frac{x}{x+8}\)According to the given condition,\(\frac{x+17}{x+8-1} = \frac{3}{2}\) \(\frac{x+17}{x+7} = \frac{3}{2}\) 3(x + 7) = 2(x + 17)

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.The rational number will be \(\frac{x}{x+8}\)According to the given condition,\(\frac{x+17}{x+8-1} = \frac{3}{2}\) \(\frac{x+17}{x+7} = \frac{3}{2}\) 3(x + 7) = 2(x + 17)3x + 21 = 2x + 34

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.The rational number will be \(\frac{x}{x+8}\)According to the given condition,\(\frac{x+17}{x+8-1} = \frac{3}{2}\) \(\frac{x+17}{x+7} = \frac{3}{2}\) 3(x + 7) = 2(x + 17)3x + 21 = 2x + 343x – 2x + 21 – 34 = 0

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.The rational number will be \(\frac{x}{x+8}\)According to the given condition,\(\frac{x+17}{x+8-1} = \frac{3}{2}\) \(\frac{x+17}{x+7} = \frac{3}{2}\) 3(x + 7) = 2(x + 17)3x + 21 = 2x + 343x – 2x + 21 – 34 = 0x – 13 = 0

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.The rational number will be \(\frac{x}{x+8}\)According to the given condition,\(\frac{x+17}{x+8-1} = \frac{3}{2}\) \(\frac{x+17}{x+7} = \frac{3}{2}\) 3(x + 7) = 2(x + 17)3x + 21 = 2x + 343x – 2x + 21 – 34 = 0x – 13 = 0x = 13

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.The rational number will be \(\frac{x}{x+8}\)According to the given condition,\(\frac{x+17}{x+8-1} = \frac{3}{2}\) \(\frac{x+17}{x+7} = \frac{3}{2}\) 3(x + 7) = 2(x + 17)3x + 21 = 2x + 343x – 2x + 21 – 34 = 0x – 13 = 0x = 13The rational number will be

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.The rational number will be \(\frac{x}{x+8}\)According to the given condition,\(\frac{x+17}{x+8-1} = \frac{3}{2}\) \(\frac{x+17}{x+7} = \frac{3}{2}\) 3(x + 7) = 2(x + 17)3x + 21 = 2x + 343x – 2x + 21 – 34 = 0x – 13 = 0x = 13The rational number will be= \(\frac{x}{x+8}\)

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.The rational number will be \(\frac{x}{x+8}\)According to the given condition,\(\frac{x+17}{x+8-1} = \frac{3}{2}\) \(\frac{x+17}{x+7} = \frac{3}{2}\) 3(x + 7) = 2(x + 17)3x + 21 = 2x + 343x – 2x + 21 – 34 = 0x – 13 = 0x = 13The rational number will be= \(\frac{x}{x+8}\)= \(\frac{13}{13+8}\)

Let the numerator of the rational number be x.So as per the given condition, the denominator will be x + 8.The rational number will be \(\frac{x}{x+8}\)According to the given condition,\(\frac{x+17}{x+8-1} = \frac{3}{2}\) \(\frac{x+17}{x+7} = \frac{3}{2}\) 3(x + 7) = 2(x + 17)3x + 21 = 2x + 343x – 2x + 21 – 34 = 0x – 13 = 0x = 13The rational number will be= \(\frac{x}{x+8}\)= \(\frac{13}{13+8}\)Rational number = 13/21

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Answer 2

The denominator of a rational number is greater than its numerator by 5 if the numerator is increased by 11 and the denominator is decreased by 14 the new number becomes 5 Find the original number