the density % gold i 19.09g/cc Find the volume
of 384 of gold
Answers
Answer:
Volume of gold present in solution,
=
Densityofgold
Massofgold
=
19g/cm
3
1.9×10
−4
g
=0.1×10
−4
cm
3
For spherical particles of gold with a radius equal to 10nm
The volume of each particle:
3
4
πr
3
=
3
4
×
7
22
×(10×10
−7
cm)
3
=
21
88
×10
−18
cm
3
Number of gold particles present:
=
Volumeofeachparticle
Volumeofgoldinsolution
=
21
88
×10
−18
cm
3
0.1×10
−4
cm
3
=
88
21
×10
13
=2.4×10
12
2.4×10
12
particles of gold are presnt in 1000cm
3
(1 litre).
∴ Number of particles present per mm
3
=
10
6
2.4×10
12
[1L=10
6
mm
3
]
=2.4×10
6
Answer:
Volume of gold present in solution,
=
Densityofgold
Massofgold
=
19g/cm
3
1.9×10
−4
g
=0.1×10
−4
cm
3
For spherical particles of gold with a radius equal to 10nm
The volume of each particle:
3
4
πr
3
=
3
4
×
7
22
×(10×10
−7
cm)
3
=
21
88
×10
−18
cm
3
Number of gold particles present:
=
Volumeofeachparticle
Volumeofgoldinsolution
=
21
88
×10
−18
cm
3
0.1×10
−4
cm
3
=
88
21
×10
13
=2.4×10
12
2.4×10
12
particles of gold are presnt in 1000cm
3
(1 litre).
∴ Number of particles present per mm
3
=
10
6
2.4×10
12
[1L=10
6
mm
3
]
=2.4×10
6