Question

The density of 1.4 molal solution of acetic acid os 1.08g/m.the molarity of the solution will be

Answer 1

Answer:

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Answer 2

Answer:

The molarity of the solution is 1.512M.

Explanation:

Given that,

Molality of acetic acid solution is $(m)=1.4m$ and

The density of the acetic acid solution is $\rho=1.08g/ml=1.08kg/L$

We know that the molality of a solution is the ratio of number of moles of solution to weight of solvent in kilograms.Therefore,

$m=\frac{n}{w(in\:kg)}\\= > 1.4=\frac{n}{w(in\:kg)}$

Dividing both the numerator and denominator with Volume(in L) we get

$1.4=\frac{\frac{n}{V(in L)} }{\frac{w(in \:kg)}{V(inL)} }$

We know that molarity is the ratio of number of moles to volume in litres and density is ratio of weight of solvent to its volume.Therefore,we write

$1.4=\frac{M}{\rho}$

Substituting the known value in above relation we get

$1.4=\frac{M}{1.08}= > Molarity=1.4\times1.08=1.512M$

Therefore,

The molarity of the solution is 1.512M.

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