The density of 3M solution of NaCl is 1.25 g mL-1
ᶜᵃˡᶜᵘˡᵃᵗᵉ ᵐᵒˡᵃˡⁱᵗʸ ᵒᶠ ᵗʰᵉ ˢᵒˡᵘᵗⁱᵒⁿ
lucifer4087:
hi
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HERE IS YOUR ANSWER MAHI....
M = 3 mol L-1
Mass of NaCl
in 1 L solution = 3 × 58.5
= 175.5 g
Mass of 1 L solution = 1000 × 1.25
= 1250 g
( since density = 1.25 g mL-1 )
Mass of water in solution
= 1250 -175.5
= 1074.5 g
= 3 mol / 1.0745 kg = 2.79 m
เ ɦσρε เƭ ɦεℓρ ყσµ ☺
M = 3 mol L-1
Mass of NaCl
in 1 L solution = 3 × 58.5
= 175.5 g
Mass of 1 L solution = 1000 × 1.25
= 1250 g
( since density = 1.25 g mL-1 )
Mass of water in solution
= 1250 -175.5
= 1074.5 g
= 3 mol / 1.0745 kg = 2.79 m
เ ɦσρε เƭ ɦεℓρ ყσµ ☺
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