Question

The density of gold is 19.3g/cm3. What is the volume, in cm3, of a sample of gold with mass 0.715 kg? If this sample of gold is a cube, how long is each edge in cm?

Answer 1

Given that density of gold is 19.3 g/cm³

Mass given = 0.715 kg = 715 g

Now, we know that density = mass/volume

So,19.3 = 715/volume

⇒ volume = 715/19.3

⇒ volume = 37.047 cm³ (approx)

Now given that the sample of gold is in the shape of cube. We know that volume of a cube = a³ where a is the side, or edge.

Therefore, 37.047 cm³ = a³

⇒ a = ∛37.047

⇒ a = 3.3336 cm (approx)

Answer :- Volume = 37.047 cm³ (approx) and edge = 3.3336 cm (approx)

Answer 2

Answer:

Given that density of gold is 19.3 g/cm³

Mass given = 0.715 kg = 715 g

Now, we know that density = mass/volume

So,19.3 = 715/volume

⇒ volume = 715/19.3

⇒ volume = 37.047 cm³ (approx)

Now given that the sample of gold is in the shape of cube. We know that volume of a cube = a³ where a is the side, or edge.

Therefore, 37.047 cm³ = a³

⇒ a = ∛37.047

⇒ a = 3.3336 cm (approx)

Answer :- Volume = 37.047 cm³ (approx) and edge = 3.3336 cm (approx)