Question

The density of liquid remains unchanged at various position . now,if the pressure at half depth is 3/5 times the pressure at its bottom then the depth of the lake

Answer 1

Depth = d

Atmospheric Pressure = P₀ = 10⁵ Pa

Density of water at 4°C (ρ) = 10³ kg/m³

Pressure at half of depth

P = P₀ + (d/2)ρg

P = P₀ + 0.5dρg

Pressure at the bottom of lake

P’ = P₀ + dρg

Given that P = 3P’/5

P₀ + 0.5dρg = 3(P₀ + dρg)/5

P₀ + 0.5dg = 3P₀/5 + 3dρg/5

Apply values and by calculation You get value of "d".

Practice Calculation URSELF.

Hope this Helpz

Naz:):)

ANY DOUBTS CAN BE ASKED IN COMMENTZZ