The density of substance decreases from 10 103 kg/m3 to 7 103 kg/m3 on heating it from 0 c to 100 c. The coefficient of linear expansion of substance is
Answers
Answer:
k = 63.9 W/m2 ·K) are heated in a furnace to 850°C and then quenched in a water bath at 50°C for a period of 40 seconds as part of a hardening process. The convection heat transfer coefficient is 650 W/m2 ·K.
Given:
The initial density of the substance = 10×10⁻³ kg/m³
The final density of the substance = 7 ×10⁻³ kg/m³
The initial temperature of the substance = 0° C
The final temperature of the substance is 100 °C
To Find:
The coefficient of linear expansion of the given substance.
Solution:
The relation between coefficient of volume expansion, and densities, and temperature difference is
γ ⇒ Δρ/ (ρΔT) = (Δρ₁ - Δρ₂)/ ρΔθ
γ ⇒ (10 - 7) / 10 × (100-0)
γ = 3 × 10⁻⁴
And relation between cefficient of volume expansion and coefficient of linear expansion
γ = 3α
So, α = γ/3 = 3 × 10⁻⁴ = 10⁻⁴
Hence, the coefficient of linear expansion of the substance is (10⁻⁴).