Question

The depth of a tank filled with a liquid is 2d.The apparent depth is 60℅ of that of real depth.What is the refractive index of the liquid w.R.T air

Answer 1

Real depth: 2d

Apparent depth: 60%of real depth

= 60× 2d=120d

Refractive index of liquid with respect to air= 3×10^8/refractive index of liquid

120d=3×10^8/d

120d2=3×10^8

D2=3×10^8/120

D=5×10^6=5000000.

Sorry,just tried...i am not sure... don't mind.

Answer 2

Answer:

The refractive index of the liquid w.r.t air is 1.67.

Explanation:

Given that,

Depth = 2d

The apparent depth is 60℅ of that of real depth.

Apparent depth$d' = 60\%\times2d$

$d' = \dfrac{60}{100}\times2d$

$d'=\dfrac{6d}{5}$

The apparent depth is equal to the real depth divided by the refractive index of the medium .

The apparent depth is defined as,

$d'=\dfrac{d}{r}$

The  refractive index of the liquid w.r.t air

$r=\dfrac{d}{d'}$

Where, d = real depth

d' = apparent depth

Put the value of d and r into the formula

$r =\dfrac{2d}{\dfrac{6d}{5}}$

$r=\dfrac{10}{6}$

$r=1.67$

Hence, The refractive index of the liquid w.r.t air is 1.67.