Question

the derivative of sec(tan^-1) with respect to x is​

Answer 1

Answer:

$let \: y = \sec( \tan {}^{ - 1}x ) \\ \frac{dy}{dx} = \sec( \tan^{ - 1} x). \tan( \tan^{ - 1}x ) \frac{1}{1 + {x}^{2} }$