Question

the derivative of the function fx=sin^2x+cos^2x with respect to x is​

Answer 1

Answer:

$\fcolorbox{red}{blue}{Let\:u\:sin2x;\:v\:=cos2x}$

$\fcolorbox{red}{blue}{on\:differenting\:w.r.t\:x\:respectively,\:we\:get}$

$\fcolorbox{red}{blue}{du\:dx\:=\:2\:sin\:x\:cos\:x\:=\:sin2x}$

$\fcolorbox{red}{blue}{du/dx\:2\:cos\:×\:sin\:x\:=\:-sin2x}$

$\fcolorbox{red}{blue}{Now,\:du/dv\:du/dx\:dv/dx}$

$\fcolorbox{red}{blue}{=\:sin2x/-sin2x\:=\:-1}$