Question

The derivative of X^x is​

Answer 1

Answer:

$=xX^{X-1}$

Step-by-step explanation:

$=\frac{d}{dx} (X^{x} )\\\\=xX^{X-1}$

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Answer 2

Answer

Let y=x

x

Applying log on both sides

logy=xlogx

Differentiating wrt x

y

1

dx

dy

=logx+

x

1

×x

dx

dy

=y(1+logx)

dx

dy

=x

x

(1+logx)