Question

the diagnals of a rhombus measure 16 cm and 30 cm find its perimeter

Answer 1

Side ^2 = (d1/2)^2 + (d2/2)^2 { Pythagoras Theorem}

=) s^2 = (16/2)^2 + (30/2)^2

=) s^2 = 8^2 + 15^2

=) s^2 = 64 + 225

=) s^2 = 289 cm^2

=) s = 17cm.

Hope it's helpful to u.

Answer 2

${s}^{2} = { \frac{d1}{2} }^{2} + { \frac{d2}{2} }^{2} \\ {s}^{2} = {15}^{2} + {8}^{2} \\ {s}^{2} = 225 +64 = 289\\ s = 17$
Perimeter of rhombus=4×side=4×17=68cm.