the diagnoals of a rhombos PQRS intersects each other at T. If PR=8cm and QS=6cm. Find the length of its sides
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since PR=8cm
then op=or=4cm
QS=6cm
then,os=oq=3cm
hence in right triangle OSR
Side^2=OS^2+OR^2
side=root under 25
side=5cm
then op=or=4cm
QS=6cm
then,os=oq=3cm
hence in right triangle OSR
Side^2=OS^2+OR^2
side=root under 25
side=5cm
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