Question

The diagnol AC and BD of a rhombus ABCD meet at O. If AC = 10cm, BD =24 cm find Sin angle OAD

Answer 1

Answer:

12/13 cm

Step-by-step explanation:

First You have to understand That Diagonals of a Rhombus perpendicularly bisect each other.

⇒AC and BD Bisect each other.

⇒AO = AC/2 = 5

also OD = 12

Now Consider ΔOAD

It is a right angled triangle since Diagonals Bisect PERPENDICULAR to each other.

⇒hypotenuse=√(OA²+OD²)=√(5²+12²)=13

Now sin(∠OAD)=opposite/hypotenuse

                        =OD/13

                         =12/13 cm

Answer 2

Answer:

THE REQUIRED ANSWER IS 12 /13

Step-by-step explanation:

We know that for a Rhombus diagonal bisects each other at right angle

Now by the given condition

AC = 10 cm

BD = 24 cm

So

OA = 5cm

OD = 12 cm

Using law of Geometry

AD = √5² + 12² = √25 + 144 = √169 = 13

SO

Sin OAD = OD / AD = 12/13

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