Question

the diagnol of arectangular piece of land is 60m more tha its smaller side if its bigger side is 30m more than the smaller side.find the dimension of the land.​

Answer 1

diagonal = 60 + breadth

lenght = 30 + breadth

let lenght be x

breadth be y

$= > x = y + 30 \\ = > \sqrt{ {x}^{2} + {y}^{2} } = 60 + y \\ = > \sqrt{ {(y + 30)}^{2} + {y}^{2} } = 60 + y \\ = > \sqrt{ {(y)}^{2} + 60y + 900+ {y}^{2} } = 60 + y \\ = > 2 {y}^{2} + 60y + 900 = {y}^{2} + 120y + 3600 \\ = > {y}^{2} - 60y - 2700 = 0 \\ = > {y}^{2} - 90y + 30y - 2700 = 0 \\ = > y(y - 90) + 30(y - 90) = 0 \\ = > y = 90 \\ = > x = 120$

dimension of rectangle is 90*120

hope it helps you

Answer 2

Answer:

the diagnol of arectangular piece of land is 60m more tha its smaller side if its bigger side is 30m more than the smaller side.find the dimension of the land.