The diagnols of a rhombus measure 16cm and 30cm.Find its perimeter
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Answered by
8
hiii!!!
here's ur answer...
diagonals of the rhombus are 16cm and 30cm.
when they bisect each other, 4 right angle triangle are formed.
the base of the triangle will be = 16/2
= 8cm
height of the triangle = 30/2
= 15cm
by Pythagoras thereom:-
a²+b² = c²
8²+15² = c²
64+225 = c²
289 = c²
c = √289
c = 17cm
hence the side of the rhombus is 17cm.
hope this helps..!
here's ur answer...
diagonals of the rhombus are 16cm and 30cm.
when they bisect each other, 4 right angle triangle are formed.
the base of the triangle will be = 16/2
= 8cm
height of the triangle = 30/2
= 15cm
by Pythagoras thereom:-
a²+b² = c²
8²+15² = c²
64+225 = c²
289 = c²
c = √289
c = 17cm
hence the side of the rhombus is 17cm.
hope this helps..!
Answered by
2
Rhombus=1/2(d1×d2) ,d1=16cm ,d2=30cm.r=240
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