The diagonal ac and bd of a parallelogram abcd intersect each other at o if anglecad=32 and angle aob=70 find angledbc
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Answer:
<DBC = 38°
Step-by-step explanation:
Given:
ABCD is a parallelogram .
AC,BD diagonals intersecting at "O".
<DAC = 32°, <AOB = 70°
Proof:
i) AB//DC , AC is a transversal.
<DAC = <BCA = 32°
/* Alternate angles */
ii) In ∆BCO , CO extended to A.
Sum of interior opposite angles = Exterior angle at O
=> <BCA + <OBC = <AOB
=> <BCA + <DBC = <AOB
=> 32° + <DBC = 70°
=> <DBC = 70°-32°
=> <DBC = 38°
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