Math, asked by Ayazbrainliest, 6 months ago

The diagonal BD of a parallelogram ABCD is bisected
at O. Through O a line is drawn, cutting BC and AD at
P and Q respectively. Prove that OP = OQ and BPDQ is
a parallelogram.

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Answered by SonalRamteke

5

$this \: is \: your \: answer \: \: brother$

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