the diagonal of a parallelogram are represented by 3i^+2j^-7k^and 5i^+6j^-3k^. find the area of parallelogram
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There is no way to find the answer with given data, the question is incomplete as parallelogram has two diagonals (Smaller and Larger). Plus you need angle between the sides to calculate the values, you can use cosine law.
c^2=a^2+b^2−2a*b*cos(C)
c^2=a^2+b^2−2a*b*cos(C)
The auestion is complete
hi
Since the question does not state which diagonal, you can safely assume the parallelogram as Rectangle and solve the problem
It's the sum of vector
We have to use component rule in This
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A = |3 2 -7| & B = |5 6 -3| A*B = i[(2x-3) - (-7x6)] - j[(3x-3) - (-7x5) ] + k[(3x6) - (2x5) ] = 36i - 26j +10k. Value = sqrt (36^2+26^2+10^2) = 45.519.. Area of parallaogram = 1/2*45.52 = 22.76
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