Question

The diagonal of a quadrilateral is 20 cm in length and the lengths of perpendiculars on it from
the opposite vertices are 8 cm and 11 cm. what is the area of the quadrilateral?​

Answer 1

Answer:

$area \: of \: quadrilateral \\ = \frac{1}{2} d \times (a + b) \\ where \\ d = given \: diagonal = 20\\ a = first \: height = 8\\ b =second \: height \: = 11 \\ area = \frac{1}{2} \times 20 \times (8 + 11) \\ = 10 \times 19 = 190 {cm}^{2}$