The diagonal of a quadrilateral shaped field is 24 m and the remaining opposite
verticles are 8 m and 13 m. Find the area of the field.
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Answer:
Let ABCD be the given quadrilateral in which BE⊥ACandDF⊥AC.
It is given that
AC=24m,BE=8mandDF=13m.
Now, area of quad. ABCD=areaofΔABC+areaofΔACD
=21×AC×BE+21×AC×DF
=(12×8+12×13)m2
=(96+156)m2=252m2
Step-by-step explanation:
hope it helps you
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