the diagonal of a quadrilateral shaped field is 24 m and the remaining opposite
verticles are 8 m and 13 m. find the area of the field.
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The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.
Question :-
Given :-
Diagonal of quadrilateral =
and
opposite vertics =
m
8
m
2
4
m
To find :-
Area of field ?¿
•
Solution :-
Area of the field = area of ∆ABD + area of ∆BCD
= \dfrac{1}{2} \times b \times h + \dfrac{1}{2} \times b \times h
= {252m}^{2}
Hence, the required area of the field
= {252m}^{2}
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