The diagonal of a rectagular field is 9m more than the shorter side. If the difference b/w the longer and the shorter side is 1m ,find the side of the field.
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Answered by
1
Answer:20,21
Step-by-step explanation:
d-b=9
a-b=1
sqr(d)=sqr(b)+sqr(a)
Replace a = b+1
d = b+9
b=20
A=20+1=21
d=29
aashishkota:
d is diagonal
a is longer side , b is short side
Answered by
0
Let the shorter side be x
Let longer side be y
Diagonal is equal to 9+x
Longer side=81+x square+17x
Since if we could see diagonal is hypotenuse ,shorter side is adjacent and longer side is opposite
According to Pythagorean’s therom hypotenuse square is equal to sum of opposite square and adjacent square
Therefore
(9+x)^2=x^2+y^2
On solving we get
Y=81+x^2+17x
Let longer side be y
Diagonal is equal to 9+x
Longer side=81+x square+17x
Since if we could see diagonal is hypotenuse ,shorter side is adjacent and longer side is opposite
According to Pythagorean’s therom hypotenuse square is equal to sum of opposite square and adjacent square
Therefore
(9+x)^2=x^2+y^2
On solving we get
Y=81+x^2+17x
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