Question

The diagonal of a rectangle abcd meet at o . If angle boc is 44, find angle oad

Answer 1

hi friend

here your answer looking for

in a given figure,

angle BOC=angle A O D. (vertically opposite angle)
so,

angle AOD =44

in triangle AOD,

angle OAD= angle ODA. (opp angles of Iso. Tri.)

angle A O D + angle OAD + angle ODA= 180

44+angle OAD + angle OAD=180

2(angle OAD)=136
angle OAD=68

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from brainly star Amaytripathi19

Answer 2

Answer:

Step-by-step explanation:

∠BOC = ∠AOD� [Vertically opposite angles are equal] ∠AOD = 70° Since diagonal of a rectangle are equal and they bisect each other. We can write OA = OB = OC = OD Hence�DAOD is an isosceles triangle. ⇒∠OAD = ∠ODA� [Angles opposite to equal sides of a triangle are equal] Let ∠OAD = ∠ODA = x ∠OAD + ∠ODA +∠AOD = 180° �⇒�x + x + 70° = 180° ⇒�2x = 110° �⇒�x = 55° Hence ∠ODA = 55