Question

the diagonal of a rectangle is 1 meter more than its length and breadth is 1 meter less than its length. find length and breadth .​

Answer 1

Answer:

Let b=x

l=x+1

d=X+2

A/Q

L^2+ B^2=D^2

(X+1)^2+ X^2 =(X+2)^2

X^2+ 1+2X +X^2=X^2+4+4X

X^2 -2X-3=0

X^2+X-3X-3=0

X(X+1) -3(X+1)=0

(X-3)(X+1)=0

SO THERE WILL BE TWO ANSWER

FIRST    (+03) AND     (-01)

SO LENGTH CAN BE IN NEGATIVE

SO B=3

L=4

AND  D=5

Step-by-step explanation:

Step-by-step explanation:

Answer 2

length of rectangle = 4 m

breadth of rectangle = 3 m

Step-by-step explanation:

let the length of the rectangle be x

breadth is 1 meter less than its length i.e x-1

diagonal is 1 meter more than its length i.e x+1

since,

angles of a rectangle is 90° i.e right angle

using the pythagoras theorem

d² = L² +B²

(x+1)² = x²+ (x-1)²

using the identity (a+b)= a²+b+2ab

x²+1+2x = x²+x²+1-2x

solving

2x+2x = x²

4x= x²

x= 4

length of the rectangle = 4 m

then breadth = x-1 = 4-1 = 3 m

hence ,

length of rectangle = 4 m

breadth of rectangle = 3 m

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