Question

The diagonal of a rectangle is 34cm and its breadth is 16cm find its length and area

Answer 1

Here is your answer
Diagonal = 34 cm
Breadth = 16 cm
Length = L

$l {}^{2} = (34) {}^{2} - (16) {}^{2} \\ l {}^{2} = 1156 - 256 \\ l = \sqrt{900} \\ l = 30cm \: \: answer \\ now \: \: \\ area = l \times b \\ = 30 \times 16 \\ = 480sq \: cm \: \: \: \: answer$
Hope it helps you

Answer 2

Solutions :-



We have,

Diagonal = 34 cm
Breadth = 16 cm

Let the length be x



Find the length of rectangle :-
We know,

(Diagonal)² = (Length)² + (Breadth)²


A/q

➣ (34)² = x² + (16)²
➣ 1156 = x² + 256
➣ x² = 1156 - 256
➣ x² = 900
➣ x² = (30)²
➣ x = 30

So,
Length = x = 30 cm




Now,
Find the area of rectangle :-
We know,

Area of rectangle = (Length × Breadth) square unit
= (30 × 16) cm²
= 480 cm²



Answer : Length of rectangle = 30 cm
Area of rectangle = 480 cm²