the diagonal of a rectangle is 5 cm and one of at sides is 4 cm .its area is?
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Answered by
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Hey! Here is ur answer...
Given :-
one side = a = 4cm
nd diagonal = h = 5cm
Let, the other side be 'b'
Now,
By applying pythgoras theorem ;
find base,
b^2 = h^2 - p^2
b^2 = (5)^2 - (4)^2
b^2 = 25 - 16
b^2 = 9
b = 3
So, the two sides are 4cm and 3cm
Then ;
Area of rect. = length × breadth
ar. = 4 × 3
ar. = 12 cm^2
Hope this helps u...Plz mark it as brainliest...☺
Given :-
one side = a = 4cm
nd diagonal = h = 5cm
Let, the other side be 'b'
Now,
By applying pythgoras theorem ;
find base,
b^2 = h^2 - p^2
b^2 = (5)^2 - (4)^2
b^2 = 25 - 16
b^2 = 9
b = 3
So, the two sides are 4cm and 3cm
Then ;
Area of rect. = length × breadth
ar. = 4 × 3
ar. = 12 cm^2
Hope this helps u...Plz mark it as brainliest...☺
Adisha01:
To get equal value of b in both cases mutiply it
multiply eq(1) with 3 and eq(2) with 2
to get b = 6 in eack cases
so now the eq becomes; a/b = 3/6 and b/c = 6/10
So, a:b:c = 9:6:10
Hope u understood!!!
If yes plz mark my ans as brainliest
in last 4th cmnt a/b is 9/6...sry i have written wrong by mistake
thanks
wlcm...☺
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