Question

the diagonal of a rectangle is 5 cm and one of its sides is 4 cm its area is​

Answer 1

Solution

Formula : h2=P2+B2

Find base,

b^2 = h^2 - p^2

b^2 = (5)^2 - (4)^2

b^2 = 25 - 16

b^2 = 9

b = 3

two sides are 4cm and 3cm

Area of rectangle = length × width  

area = 4 × 3

final answer:

area = 12 cm^2

Step-by-step explanation:

I hope this helped.

Answer 2

Answer:

Hey Mate!!

In a rectangle, the diagonal divides it into 2 right angled triangles.

$= > {(side \: 1)}^{2} + {(side \: 2)}^{2} = {(diagonal)}^{2} \\ = > {4}^{2} + {(side \: 2)}^{2} = {5}^{2} \\ = > {(side \: 2)}^{2} = 25 - 16 \\ = > side \: 2 = \sqrt{9} \\ = > \bold{side \: 2 = 3 \: cm}$

Therefore, area of rectangle = l × b

••> 4 × 3

••> 12 cm^2