the diagonal of a rectangle is 5cm and one of at sides is 4 cm .its area is
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Here the diagonal becomes the hypotenuse i.e. 5cm and 4cm is its one of side so let it be the base of rectangle
Now, Apply Pythagoras theorem,
H²=B²+P²
(5)²=B²+(4)²
B²=25-16→B²=9→B=±3
But ,we take only positive value bcz we ae talking about Area...
Now ,Area of rectangle =
So it is A=3×4=12cm²
Hope it helps...so plz mark it as a brainliest answer
Now, Apply Pythagoras theorem,
H²=B²+P²
(5)²=B²+(4)²
B²=25-16→B²=9→B=±3
But ,we take only positive value bcz we ae talking about Area...
Now ,Area of rectangle =
So it is A=3×4=12cm²
Hope it helps...so plz mark it as a brainliest answer
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