Question

the diagonal of a rectangular Courtyard is 61 M if the length is 60 m find the area of the courtyard

Answer 1

$\text{Given...}\\Length = 60 \ m \\Diagonal = 61 m\\\\We \ know\\Pythagoras \ Theorem,\\H^2 = B^2 + P^2\\(BD)^2 = (BC)^2 + (CD)^2\\(61)^2 = (BC)^2+(60)^2\\3721 - 3600 = BC^2\\\sqrt{121} = BC\\BC = 11\\\\Now,\\Area = l\times b\\Area = 60\times 11\\\boxed{\boxed{Area = 660 cm^2}}$

Answer 2

$Hey \: there !!$
$Let \: \: l \: \: and \: \: b \: \: be \: the \: \: dimensions \: of the \: rectangle$
Given That


∘ ABCD is the rectangle in which➯

l. , CD = 60 m

Diagonal , BC = 61 m

Breadth , BD = ?


Using Pythagoras Theorem -

${BC \: }^{2} = {C D \: }^{2} + {BD }^{2}$

➪ 61² = 60² + BD²

➪BD ² = 3721 - 3600

➪ BD ² = 121

➪ BD = 11 m



So , area of Rectanglular Courty yard , = l × b

➪ CD × BD


➪ 60 × 11

➪ 660 m²


⊛ Hope this would help you ⊛