Question

the diagonal of a rectangular field ABCD is X + 9 and the side are X + 7 and X find the value of x​

Answer 1

Answer:

$\because {(diagonal)}^{2} = {(one \: side)}^{2} + {(other \: side)}^{2} \\ \therefore {(x + 9)}^{2} = {(x + 7)}^{2} + {x}^{2} \ \\ {x}^{2} + 18x + {9}^{2} = {x}^{2} + 14x + {7}^{2} + {x}^{2} \\ {x}^{2} + 18x + 81 = 2{x}^{2} + 14x + 49 \\ 2 {x}^{2} + 14x + 49 - {x}^{2} - 18x - 81 = 0 \\ {x}^{2} - 4x - 32 = 0 \\ {x}^{2} - 8x + 4x - 32 = 0 \\ x(x - 8) - 4(x - 8) = 0 \\ (x - 8)(x - 4) = 0 \\ x - 8 = 0 \: or \: x - 4 = 0 \\ x = 4 \: or \: x = 8$

Answer 2

Answer:

sorry but I could not understand ur question