Math, asked by BrainlyHelper, 1 year ago

The diagonal of a rectangular field is 60 meters more than the shorter side. If the longer side is 30 meters more than the shorter side, find the sides of the field.

Answers

Answered by nikitasingh79
83

SOLUTION :

Let the shorter side of the rectangular field be 'x' meters.

Longer side be (x + 30) m

Length of the diagonal be (x + 60) m

A.T.Q

In rectangle, the diagonal divides the rectangle into two right angled triangles.

By using  Pythagoras Theorem,

H² = P² + B²

(Diagonal)² = (Smaller Side)² + (Longer Side)²

(x + 60)² = (x)² + (x + 30)²

[x² + 60² + 2x × 60 ] = x² + [x² + 30² + 2 x × 30 ]

[(a + b) ² = a² + b² + 2ab]

x² + 120x + 3600 = x² + x² + 60x + 900

x² + 120x + 3600 = 2x² + 60x + 900

2x² - x² + 60x - 120x + 900 - 3600 = 0

x² - 60x - 2700 = 0

- 90x + 30x - 2700 = 0

[By middle term splitting]

x(x - 90) + 30(x - 90) = 0

(x - 90) (x + 30) = 0

(x - 90) = 0  or  (x + 30) = 0

x = 90  or x = - 30

Since, side can't be negative ,so x ≠ - 30 .  

Therefore , length of the shorter side is 90 m.

The length of the longer side = (x + 30) = 90 + 30 = 120 m

Hence, the length of the longer side (length) is 120 m & the length of the shorter side(breadth) is 90 m.

HOPE THIS ANSWER WILL HELP YOU….

Answered by BrainlyQueen01
69

Answer :


Shorter side = 90 m


Longer side = 120 m


Step-by-step explanation :


Let ABCD be a rectangular field. And AC be its diagonal.


Let the shorter side be x metres.


i.e., AB = x metres.


It is given that ;


The diagonal of a rectangular field is 60 meters more than the shorter side.


AC = AB + 60


AC = x + 60


Also, longer side is 30 meters more than the shorter side.


BC = AB + 30


BC = x + 30


In ∆ABC ,


∠B = 90°             [∵ All angles of rectangle are right angles]


Hence, ABC is a right angled triangle.


By Pythagoras theorem ;


Hypotenuse² = Base² + Height²


AC² = AB² + BC²


(x + 60)² = x² + (x + 30)²


x² + 60² + 2 * x * 60 = x² + x² + 30² + 2 * x * 30


x² + 3600 + 120x = x² + x² + 900 + 60x


x² + 3600 + 120x - x² - x² - 900 - 60x = 0


x² - x² - x² + 120x - 60x + 3600 - 900 = 0


- x² + 60x + 2700 = 0


0 = x² - 60x - 2700


⇒ x² - 60x - 2700 = 0


By splitting the middle term ;


x² - 90x + 30x - 2700 = 0


x ( x - 90 ) + 30 ( x - 90 ) = 0


( x - 90 ) ( x + 30 ) = 0


x = 90 or x = - 30


So, x = 90 and x = - 30 are the roots.


Since, x is the length, it can not be negative.


Therefore, x = 90


Shorter side = x = 90 metres.


Longer side = x + 30


                   = 90 + 30


                   = 120 metres.


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