Question

The diagonal of a rectangular field is 60 metres more than the shorter side. If the longer
side is 30 metres more than the shorter side, find the sides of the field.
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Answer 1

Answer:

120m,90m

Step-by-step explanation:

Let the sides of the rectangle be l,b (l>b) and diagonal be d

Given: d= 60+b; l=30+b

We know d=√(l²+b²)

d²= l² + b²

Substituting,

(60+b)² = (30+b)² +b²

3600 + b² + 120b = 900 + b² + 60b +b²

b²= 3600 -900 +120b -60b

b² = 2700 + 60b

b² - 60b -2700 =0

b² -90b + 30b -2700=0

b(b-90) + 30(b-90)=0

(b+30)(b-90)=0

b=-30,90

Since b is the breadth of a rectangle it can be positive only

so b=90m

l=b+30=90+30=120m

The sides of the rectangle are 120m,90m

Answer 2

Answer:

this is your ans

I hope it helps