The diagonal of a rectangular field is 60meters more than the shorter side. If the longer side is 30 meters more than the shorter side, find the sides of the field.
Answers
Answered by
3
let digonal be x
shorter side be y
x = y + 60
x = 90
use Pythagoras and find side
Answered by
5
let shorter side(b) be x
diagonal(d) = 60+x
length or longer side(l) =30+x
By pythagoras theorem:-
d^2=l^2 + b^2
(60+x)^2=(30+x)^2 + x^2
3600+x^2+120x=900+x^2+60x+x^2
x^2-60x-2700=0
x^2-(90-30)x-2700=0
x^2-90x+30x-2700=0
x(x-90)+30(x-90)=0
(x-90)(x+30)=0
x=90,-30
side cannot be negative
so , x=90
b=90m
and l=30+x
=30+90 =120m
diagonal(d) = 60+x
length or longer side(l) =30+x
By pythagoras theorem:-
d^2=l^2 + b^2
(60+x)^2=(30+x)^2 + x^2
3600+x^2+120x=900+x^2+60x+x^2
x^2-60x-2700=0
x^2-(90-30)x-2700=0
x^2-90x+30x-2700=0
x(x-90)+30(x-90)=0
(x-90)(x+30)=0
x=90,-30
side cannot be negative
so , x=90
b=90m
and l=30+x
=30+90 =120m
satwikmandi100p6o19x:
Thank you Shreya it was really helpful .......
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