Math, asked by maheshwarividhushi, 20 days ago

the diagonal of a rectangular park is 10 m. if its sides are in the ratio 4:3 , find the cost of femcing at Rs.15 per metre​

Answers

Answered by ImperialGladiator
3

Answer:

₹420

Explanation :

Given ratio :

  • Length : breadth = 4 : 3

Diagonal :

  • 10 metres.

Let's assume :

  • length = 4x
  • Breadth = 3x

By Pythagoras theorem,

→ 4x² + 3x² = 10²

Solving for x

→ 16x² + 9x² = 100

→ 25x² = 100

→ x² = 100/25

→ x² = 4

→ x = √4

→ x = 2 units.

The value of x is 2 units.

Hence, the dimensions are :

  • length = 4x = 8 metres.
  • breadth = 3x = 6 metres.

Fencing of the park = Perimeter of a rectangle

  • Perimeter of a rectangle is 2(l + b).

So, the fencing is

→ 2(8 + 6)

→ 2(14)

→ 28 metres.

Cost of fencing : rate of fencing × fencing

Where,

the rate is ₹15 per metre.

So,

→ 15 × 28

→ ₹420

Required answer : ₹420

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