Question

construct a triangle ABC , in which BC=10cm B=45 and AB-AC=5cm give justification​

Answer 1

Step-by-step explanation:

Draw base BC of length 10 cm.

Now, let's draw ∠B=45. ∘ .Let the ray be BX.

Open the compass to length AB−AC= 5cm. Since AB−AC=5cm is positive. ...

Join CD.

Now, we will draw perpendicular bisector of CD.

Mark point A where perpendicular bisector intersects BD.

Join AC.

Hope it will help you..