Math, asked by hardeep1085, 3 months ago

The value of 1+1+i+(1+i)^2+(1+i)^3?

Answers

Answered by rakeshdubey33
2

Answer:

5i

Step-by-step explanation:

Given :

1 + (1 + i) \:  +  {(1 + i)}^{2}  +  {(1 + i)}^{3}

Here,

 {(1 + i)}^{2}  = 1 +  {i}^{2}  + 2i \\  = 1 - 1 + 2i \\  = 2i \\ and \\  {(1 + i)}^{3}  =  {(1 + i)}^{2}  \times (1 + i) \\  = 2i \times (1 + i) \\  = 2i + 2 {i}^{2}  \\  = 2i - 2

Therefore,

1 + (1 + i) +  {(1 + i)}^{2}  +  {1 + i)}^{3}  \\  = 2 + i + 2i + 2i - 2 \\  = 5i

Note : \:  {i}^{2}  =  - 1

Hence, the answer is 5i

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