the diagonal of a rhombus are 30 cm and 16 cm find its area the length of a side and its perimeter
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Answered by
149
area = 1/2 × product of diagonals
so area = 1/2 × 30 ×16 = 240 cm²
also diagonals bisect each other at right angles
so 1/2×30= 15cm,,,, 1/2×16 =8cm
therefore by Pythagoras theorem,
15² + 8² = side²
√289 = side
side = 17 cm
thus perimeter = 4 × 17 = 68 cm
so area = 1/2 × 30 ×16 = 240 cm²
also diagonals bisect each other at right angles
so 1/2×30= 15cm,,,, 1/2×16 =8cm
therefore by Pythagoras theorem,
15² + 8² = side²
√289 = side
side = 17 cm
thus perimeter = 4 × 17 = 68 cm
Answered by
88
The area and perimeter of rhombus is 240 square cm and 68 cm respectively.
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