Question

the diagonal of a rhombus are 8cm and 6 cm. find (1) area (2) perimeter

Answer 1

hi,

as we know that the area of rhombus is (product of diagonals)/2

here, area of rhombus = (8*6)/2 = 8*3 = 24cm^2

and 

2)-

by pythagoras theorem,

(half of I diagonal)^2 + (half of second)^2 = side^2 ]

(8/2)^2 + (6/2)^2 = side^2

4^2 +3^3 = side^2

16+9 = side^2

25= side

5cm = side


now, perimeter of rhombus = 4*side 

here,, perimeter = 4*5 =20 cm 


i hope this will help you

- by ABHAY 

Answer 2

Heya!

Here's Your Answer
____________________________

Since,
The Area Of Rhombus is
D1*D2/2
8cm*6cm/2
48 cm sq. /2
24 cm sq.

Since,
The Perimeter of Rhombus is
4*Side
Since,
Diagonals are equal,
1st diagonal half is : 8/2 = 4cm
2nd diagonal half is : 6/2 = 3cm
By,
Pythagoras Theorem,
H^2=P^2+B^2
H^2=4^2+3^2
H^2=16+9
H^2=25
H=√25
H=5cm
Therefore, One side is 5 cm

Now,
Perimeter=4*side
4*5cm
20cm -(2)

Hence,
Perimeter is : 20 cm
Area is : 24 cm sq.
_______________________________

Hope It Helps...........!!!!!

:-)