the diagonal of a rhombus is 48cm and 20cm long.find the perimeter
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Perimeter of a Rhombus = 2√(p2+q2) Given, p=48 q=20 Perimeter of a Rhombus = 2√(482+202) =2√(2304+400) =2√(2704) =2*52 =104 cm2
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h sq.=b sq. +p sq.
h sq.= 48 sq + 20 sq.
h sq. = 48*48 + 20*20
h sq.=2304+400
h sq.= 2704
h= √2704
h = 52 c.m
so in the rhombus all sides are equal 52×4
peremeter of the rhombus is 208 c.m
if it is correct reply me please
h sq.= 48 sq + 20 sq.
h sq. = 48*48 + 20*20
h sq.=2304+400
h sq.= 2704
h= √2704
h = 52 c.m
so in the rhombus all sides are equal 52×4
peremeter of the rhombus is 208 c.m
if it is correct reply me please
ushajoshiudrperzaa:
the answer is not correct
chaitanya4030 told the right answer
thanks
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