Question

the diagonal of a rhombus measure 10 cm and 24 cm . find its perimeter​

Answer 1

Step-by-step explanation:

perimeter of diagonal =2×(1/2×d1×d2/2) = 2×1/2×24×10/2 =120

Answer 2

Answer:

52 cm

Step-by-step explanation:

Diagonals of a rhombus are perpendicular bisectors of each other.

Therefore a right angle triangle is formed in side the rhombus with base 10/2 = 5 & height 24/2 = 12.

The hypotenuse of this right angle triangle is the side of the rhombus.

By Pythagoras Theorem.

(Height)² + (Base)² = (Hypotenuse)²

5² + 12²

25 + 144

169

(Hypotenuse)² = 169

Hypotenuse = 13

Hypotenuse = side

Therefore side is also 13 cm.

Now, in rhombus all sides are equal.

Therefore, perimeter is 4 × (side)

Therefore perimeter of the rhombus is 52 cm.