Question

The diagonal of a rohmbus are 8cm and 6cm in length ,calculate it perimeter

Answer 1

Answer:

Let ACD is a rhombus.

Diagonal AC = 8

Diagonal BD = 6

Since diagonals bisect each other at right angles at 0.

so OA = 4 and OB = 3

In right triangle OAB

AB^2 = 4^2 + 3^2 = 16 + 9 = 25

AB = 5cm

so Perimeter of rhombus = 4 × side = 4 × 5 = 20 cm

Answer 2

Answer:

this is correct............................