The diagonal of a square field is 5root 2. Find its perimeter and area.
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let the side of square be 'a',
By applying Pythagoras theorem
a^2+a^2 = d^2
2a^2 = d^2
d = a√2
d = 5√2 = a√2
a = 5
•perimeter = 4a
= 4×5
= 20
•Area = a×a
=5×5
= 25
By applying Pythagoras theorem
a^2+a^2 = d^2
2a^2 = d^2
d = a√2
d = 5√2 = a√2
a = 5
•perimeter = 4a
= 4×5
= 20
•Area = a×a
=5×5
= 25
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