the diagonal of a square is 12 cm long, find its area n length of one side
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solution:-
• we know the all angles of square are of 90°
• all side of square are equal and diagonals are equal.
so,
let, diagonal is hypotenuse
now, by Pythagoras theorem
S = side.
=> (1st S)²+(2cd S)² =(Hypotenuse)²
=> x² + x² = (12)²
=> 2x = 12
=> x = 12/2
=> x = 6
length of sides of square are 8 cm.
=> Area of square = (side) × (side)
=> Area of square = 6 × 6
=> Area of square = 36 cm².
√=> perimeter of square = 4×(side)
√=> perimeter of square = 4 × 6
√=> perimeter of square = 24 cm
6 cm , 36 cm² and 24cm are length of side , area and perimeter of the square respectively.
i hope it helps you.
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