Math, asked by Nikhil5527, 10 months ago

The diagonal of a square is 84.6cm long find the length of its side and area (Take π2 =1.41

Answers

Answered by gurjan12singh12
4

Step-by-step explanation:

diagonal=root side^2+side^2

let side is x

84.6=rootx^2+x^2

84.6=root 2x^2

84.6 = xroot2

x=84.6/root2

= 84.6/root2+root2/root2

=84.6root2/2

= 42.3root2

side of squre is 42.3root2

and now we find area

area=a^2 ( a is side )

= (42.3root2)^2

=3578.58cm2

i hope it helps you

please mark my answer

Answered by abinivas
4

Answer:

Diagonal = square root of 2+square root of side

Let side be x

84.6=square root of x²+x²

84.6=square root of 2x²

84.6=x square root of 2

X=84.6÷square root of 2+square root of 2÷square root of 2

X= 84.6÷square root of 2

X=84.6÷1.41 (since take square root 2 as 1.41)

Side = 60 cm

Area=a²

=60²

=3600 cm²

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