Question

the diagonal of rectangle is 5cm and one of its side is 4cm .find its area​

Answer 1

Answer:

Hey! Here is ur answer...

Given :-

one side = a = 4cm

nd diagonal = h = 5cm

Let, the other side be 'b'

Now,

By applying pythgoras theorem ;

h { }^{2} = p {}^{2} + b { }^{2}h

2

=p

2

+b

2

find base,

b^2 = h^2 - p^2

b^2 = (5)^2 - (4)^2

b^2 = 25 - 16

b^2 = 9

b = 3

So, the two sides are 4cm and 3cm

Then ;

Area of rect. = length × breadth

ar. = 4 × 3

ar. = 12 cm^2

Hope this helps u...Plz mark it as brainliest...☺

Answer 2

Question :-

The diagonal of rectangle is 5 cm and one of its side is 4 cm .find its area

Answer :-

→ Area = 12 cm ² .

To find :-

→ Area of rectangle

Formula used :-

$\sf{ \red{area \: of \: rectangle \: }= \green{length \times width}}$

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Step - by - step explanation :-

According to the question,

Given that ,

One diagonal of rectangle is 5 cm

and one side is 4 cm ,

According to the given attachment

ABCD is a rectangle whose CB is diagonal of length 5 cm and AB is one side of length 4 cm ,

→ AB = 4 cm and CB is 5 cm ,

To find the another side of this rectangle we have to use Pythagoras theorem in ∆ ABC ↓

→CB ² = AB ² + AC ²

→ 5 ² = 4 ² + AC ²

→ AC ² = 25 - 16

→ AC ² = 9

→ AC = 3 cm ,

Therefore ,

Area of this rectangle =(AC) × ( AB)

→ 4 × 3

→ 12 cm ² .

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