The diagonal of rhombus are 8 cm and 6 cm .find the perimeter of the Rhombus
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AS WE KNOW THE DIAGONALS OF RHOMBUS BISECT EACH OTHER AT RIGHT ANGLE
WE GET, A RIGHT ANGLE TRIANLE WHOS HEIGHT AND BASE IS 4CM AND 3CM RESPECTIVELY.
BY PYTHAGORAS THEOREM
HYPOTENUSE²=HEIGHT²+BASE²
HYPO²(SIDE OF RHOMBUS)=4²+3²
HYPO²=16+9
HYPO=√25
=5CM
PERIMETER=4*SIDE(AS THE SIDES OF RHOMBUS ARE EQUAL)
=4*5
=20CM
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