The diagonal of rhombus measure 16cm and 12cm . find its perimeter
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Answer:
Perimeter of Square = 40 cm
Step-by-step explanation:
As we know that the diagonals of the rhombus are perpendicular to each other and intersect at a point which is mid of both the diagonal.
So. By Pythagoras Theorem we can say that
(Hypotenuse)²=(Base)²+(Perpendicular)²
(Side)²= ()² + ()²
= 8² + 6²
=64 + 36
(Side)² = 100
Side = √100
Side = 10 cm
Perimeter of Square = 4 x Side
= 4 x 10
= 40 cm
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