Question

The diagonal of rhombus measures 10cm and 24cm.find its perimeter​

Answer 1

Answer:

$In \: rhombus \: the \: diagonals \: are \\ \: perpendicular \:bisector \: of \: each \\ other \\ so \\ each \: side = \sqrt{{ (\frac{24}{2}) }^{2} + {( \frac{10}{2} )}^{2}} \\ = \sqrt{{12}^{2} + {5}^{2}} = \sqrt{144 + 25} \\ = \sqrt{169} = 13 \\ perimeter \: of \: the \: rhombus \\ = 4 \times side \\ = 4 \times 13 = 52cm\\</p><p>\red \star \underline \mathcal{PLS.\:MARK\:AS\:BRAINLIEST} \red \star</p><p>$