Question

The diagonal of square is 12 root 2 cm. Find its perimeter

Answer 1

the side of the square be s.
so,
 [tex]s ^{2} + s^{2} = (diagonal)^{2} [/tex]

[tex]2s^{2} =288 [/tex]
[tex]s^{2} =144 [/tex]
$s=12$

PERIMETER=4 X SIDE= 4 X 12=48 cm

Answer 2

Here's ur answer dear......